2^x+2-4*5^x+2=25*5^x-4*2^x

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Solution for 2^x+2-4*5^x+2=25*5^x-4*2^x equation: 



2^x+2-4*5^x+2=25*5^x-4*2^x

We move all terms to the left:

2^x+2-4*5^x+2-(25*5^x-4*2^x)=0

We add all the numbers together, and all the variables

2^x-4*5^x-(25*5^x-4*2^x)+4=0

Wy multiply elements

2^x-20x-(25*5^x-4*2^x)+4=0

We get rid of parentheses

2^x-20x-25*5^x+4*2^x+4=0

We add all the numbers together, and all the variables

-20x+2^x-25*5^x+4*2^x+4=0

Wy multiply elements

-20x+2^x-125x+8x+4=0

We add all the numbers together, and all the variables

-137x+2^x+4=0

We move all terms containing x to the left, all other terms to the right

-137x+2^x=-4

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